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4x^2+9x-122=0
a = 4; b = 9; c = -122;
Δ = b2-4ac
Δ = 92-4·4·(-122)
Δ = 2033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2033}}{2*4}=\frac{-9-\sqrt{2033}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2033}}{2*4}=\frac{-9+\sqrt{2033}}{8} $
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